2x^2+5x+39=0

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Solution for 2x^2+5x+39=0 equation:


Simplifying
2x2 + 5x + 39 = 0

Reorder the terms:
39 + 5x + 2x2 = 0

Solving
39 + 5x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
19.5 + 2.5x + x2 = 0

Move the constant term to the right:

Add '-19.5' to each side of the equation.
19.5 + 2.5x + -19.5 + x2 = 0 + -19.5

Reorder the terms:
19.5 + -19.5 + 2.5x + x2 = 0 + -19.5

Combine like terms: 19.5 + -19.5 = 0.0
0.0 + 2.5x + x2 = 0 + -19.5
2.5x + x2 = 0 + -19.5

Combine like terms: 0 + -19.5 = -19.5
2.5x + x2 = -19.5

The x term is 2.5x.  Take half its coefficient (1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
2.5x + 1.5625 + x2 = -19.5 + 1.5625

Reorder the terms:
1.5625 + 2.5x + x2 = -19.5 + 1.5625

Combine like terms: -19.5 + 1.5625 = -17.9375
1.5625 + 2.5x + x2 = -17.9375

Factor a perfect square on the left side:
(x + 1.25)(x + 1.25) = -17.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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